In a cross between two doubly heterozygous ursa gummi, we observe 461 melting ursa gummi and 39 melting-resistant ursa gummi. if the melting phenotype is the dominant phenotype, make a decision as to whether these data are consistent with the duplicate dominant epistatic mode of inheritance. make your decision based on a significance level threshold of 5%.

Yes they are. chisquare p-value >0.05

Consider the following calculations

Step-by-step explanation:

A codes for melting : aa codes for melting resistance

Bcodes for melting :bb codes for melting resistance

if apunnet squrae is formed on the basis of this it shows the occurrence of duplicate dominance epistasis ratio 15:1

Chi2 values are calculated according to the formula: (Observed Value – Expected Value)2 ÷ (Expected Value)

nope.   happens to me as well.

-aparri

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry