Aparabolic arch needs to be 5m high and 2m wide at ground level. find the quadratic equation which describes the arch.

Step-by-step explanation:

Given height of parabola is .

And wide at ground level.

Also, the parabola opens down.

Let us assume the parabola is aligned on Y-axis

As the height of parabola is . The maximum height of parabola is achieved when .

So, the vertex of parabola is .

The equation of parabola having vertex is.

.

Plugging the vertex of parabola

.

It is given that parabola is wide at the ground.

As the parabola is aligned on Y-axis. So, distance between X-intercept is .

The X-intercept would be

Plugging in the equation

Now, we get and having vertex .

So, the equation of parabola is

.

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it