Many people believe that the daily change of price of a company's stock on the stock market is a random variable with mean 0 and variance 2. that is, if yn represents the price of the stock on the n-th day, then yn = yn-1 + xn, n > 1 where x1, x2, . . are independent and identically distributed random variables with mean 0 and variance 2. suppose that the stock's price today is 100. if 2 = 1, use clt to approximate the probability that the stock's price will exceed 105 on the 10-th day?

Step-by-step explanation:

We can use normal aproximation, assuming that the random variables are a lot of that means the sample size is large.

Using the normal distribution table,

P(z>5) = 0.00005

Hence, we can conclude that the probability that the stock’s price will exceed 105 after 10 days is very small.

Hope this helps!

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

company a

step-by-step explanation:

using the linear regression models , it is found that company a   pays about $14 more. but using the same regression (linear) company b pays about $10 more.

so company a pays more than b