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what is the solution to the following system of equations?

x − 4y = 6
2x + 2y = 12

(0, 10)
(10, 0)
(6, 0)
(0, 6)

(0,6)

Step-by-step explanation:

1. Arrange both equations to be equal to y which is y=6-x/-4 and y=12-2x/2

2. set the equal to each other: 6-x/-4=12-2x/2 and solve for x

3. Plug the x value of 6 into one of the original equations (we'll do x-4y=6) to get (6)-4y=6

4. Solve for y

5. The y coordinate is 0, and the x coordinate is 6, so (0,6)

The correct answer is C. (6,0).

Step-by-step explanation:

1. Arrange both equations to be equal to y which is y=6-x/-4 and y=12-2x/2

2. Set the equal to each other: 6-x/-4=12-2x/2 and solve for x6-x/-4=12-2x/2 cross multiply to get 2(6-x)=-4(12-2x) and distribute to get 12-2x=-48+8x Subtract 12 from both sides:-2x=-60+8x subtract 8x from both sides: -10x=-60 divide by 10 on both sides: x=6

3. Plug the x value of 6 into one of the original equations (we'll do x-4y=6) to get (6)-4y=6

4. Solve for y subtract 6 from both sides: -4y=0 Divide by -4 on both sides: y=05. The y coordinate is 0, and the x coordinate is 6, so (6,0).

For the solution, the x coordinate always comes first, then the y coordinate.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: