Carmen is using the quadratic equation (x + 15)(x) = 100 where x represents the width of a picture frame. which statement about
the solutions x = 5 and x = -20 is true?
the solutions x = 5 and x = -20 are reasonable.
the solution x = 5 should be kept, but x = -20 is unreasonable.
the solution x = -20 should be kept, but x = 5 is unreasonable.
the solutions x = 5 and x = -20 are unreasonable.

The solutions x = 5 and x = -20 are reasonable

Step-by-step explanation:

The equation (x+15)(x)=100=x^2+15x=100

This equals x^2+15x-100=0

The general formula is

((-b+/-Sqrt(b^(2)-4ac))/(2a))

and a is 1, b is 15 and c is -100

So ((-15 +/- Sqrt(225-(-400))/(2))

((-15 +/- Sqrt(625))/(2))

(-15+/- 25)/(2)

x= (-15 + 25)/2

=10/2

=5

OR

x=(-15-25)/2

=-40/2

=-20

The solutions x = 5 and x = -20 are reasonable

Step-by-step explanation:

edge 2020

the answer for your question is

step-by-step explanation: