Asap! what are the vertical asymptotes of the function f(x) = the quantity of 3x plus 9, all over x squared plus 4x minus 12?

a) x = −6 and x = −2
b) x = −6 and x = 2
c) x = 1 and x = −2
d) x = 1 and x = 2

B) x = -6  and  x = 2

Step-by-step explanation:

can be rewritten as

because

-2 · 6 = -12

-2 + 6 = -4

so thats why the denominator is (x+6)(x-2)

A vertical asymptote is where the denominator equals 0, so,

-6 + 6 = 0

2 + -2 = 0

So the Answer is:

B) x = -6  and  x = 2

what do u need to know

step-by-step explanation:

60: 45 =12: 9 =4: 3 so the answer is 4: 3