Solve for x in the equation x2 - 14x+31 = 63-
0
x= -16 or x = 2
x=-7+3.17
x=-2 or x = 16
x= 7+3/7
0
0

Solve for x in the equation x^2 - 14x + 31 = 63?

The value of x for given equation is x = 16 or x = -2

Given that equation is

To find: value of "x"

Subtract 63 from both sides we have:

Now we will factor our given quadratic equation by splitting the middle term.

-14x can be splitted as -16x + 2x

Take "x" as common from first two terms and "2" as common from last two terms

Take (x-16) common we have:

Equating the terms to 0,

x - 16 = 0 or x + 2 = 0

x = 16 or x = -2

Therefore, the value of x are: 16 and -2

no

step-by-step explanation:

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -