The length of a swimming pool is 3 feet longer than it's width. the swimming pool is surrounded by a deck that is 2 feet wide and has an area of 116 square feet. find the dimensions of the pool

The Dimension of the pool is approximately 5.37 feet and 8.37 feet.

Step-by-step explanation:

Given:

Area of Swimming Pool = 116 sq. ft

The length of a swimming pool is 3 feet longer than it's width.

Let the width of swimming pool be 'x' feet.

∴Length  = feet

Also given :

The swimming pool is surrounded by a deck that is 2 feet wide.

Hence we can say the deck is surrounded 2 feet on all 4 sides.

hence;

Length of swimming pool  will become =

Width of swimming pool will become =

Since Swimming pool is in rectangular shape.

Now we know that area of Swimming pool is equal to length multiplied by width.

Framing in equation form we get;

Substituting the given values we get;

Solving the equation we get;

Now solving this equation by using quadratic formula we get;

According to the Quadratic Formula,  x  , the solution for    , where  a, b  and c are numbers, often called coefficients, is given by :

in our case a = 1 , b = 11 and c = -88

, rounded to 4 decimal digits, is  21.7486.

Two real solutions:

OR

Since width of the swimming pool cannot be negative value

hence we will consider

Rounding to nearest hundred we get;

Width of Swimming pool = 5.37 feet

Length of Swimming pool = 3+5.37 =8.37 feet

Hence The Dimension of the pool is approximately 5.37 feet and 8.37 feet.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: