Suppose the functions f and g and their derivatives have the following values at x=1 and x=2. let h(x) = f(g( evaluate h'(1).

Step-by-step explanation:

Given:

The values of are given as:

Differentiating both sides with respect to 'x'. This gives,

Now, in order to find , plug in 1 for 'x'. This gives,

Now, plug in

Now, plug in

Hence, the value of is .

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

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