89.1.19-g

find the expected payback for a game in which you bet $8 on any number from 0 to 99. if your number comes up you get $400

the expected payback is

(round to the nearest cent as needed.)

enter your answer in the answer box and then click check answer.

$48.00

-$4

Step-by-step explanation:

The expected payback formula is the sum of probability multiply the value

E(x) = p(x1)*x1 + p(x2)*x2 +

In this case, we have two possibility of payback

1) winning

The payback is $400 -$8 = $392

x1 = 392

The probability of winning is one out of 100 (since the choices are 0 to 99)

p(x1) = 1/100

2. Losing

The payback is -$8 since the person didn't win anything is loose

x2 = -8

Since there is only one winning number, the other 99 numbers are loosing numbers

p(x2) = 99/100

Therefore expected payback is

E(x) = p(x1)*x1 + p(x2)*x2

= (1/100)*392 + (99/100)*(-8)

= -400/100

= -$4

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1