Automated manufacturing operations are quite precise but still vary, often with distributions that are close to normal. the width in inches of slots cut by a milling machine follows approximately the n(0.8750, 0.0012) distribution. the specifications allowslot widths between 0.8725 and 0.8775 inch. what proportion of slots meet these specifications?

96.2% of slots meet these specifications.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.8750

Standard Deviation, σ = 0.0012

We are given that the distribution of width in inches of slots is a bell shaped distribution that is a normal distribution.

Formula:

P( widths between 0.8725 and 0.8775 inch)

96.2% of slots meet these specifications.

step-by-step explanation:

if x = 2 you have to find x to finish the problem

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