Suppose at a large university, 60% of the students have a visa card and 40% of the students have a mastercard. also, 30% of the students neither have 1 a visa card, nor have a mastercard. randomly select a student from the university. given that this student has a visa card, what is the probability that this student also has a mastercard1. calculate the probability that this student does not have a mastercard. 2. calculate the probability that this student has either a visa card or a mastercard. 3. calculate the probability that this student has neither a visa card nor a mastercard. 4. are the events a and b disjoint? are the events a and b independent?

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

2.  the probability that this student has either a Visa card or a MasterCard.

=

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

=

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

the answer is 8

step-by-step explanation:

3.14 x 8x8

i dont know

step-by-step explanation: