The television show degenerate housewives has been successful for many years. that show recently had a share of 18, meaning that among the tv sets in use, 18% were tuned to degenerate housewives. assume that an advertiser wants to verify that 18% share value by conducting its own survey, and a pilot survey begins with 12 households have tv sets in use at the time of a degenerate housewivesbroadcast. find the probability that none of the households are tuned to degenerate housewives. p(none) = find the probability that at least one household is tuned to degenerate housewives. p(at least one) = the probability that at most one household is tuned to degenerate housewives. p(at most one) = at most one household is tuned to degenerate housewives, does it appear that the 18% share value is wrong? (hint: is the occurrence of at most one household tuned to degenerate housewives unusual? )

Step-by-step explanation:

Given that the television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives.

Each household is independent of the other and there two outcomes.

X no of households that are tuned to Degenerate Housewives. is Bin (12, 0.18)

the probability that none of the households are tuned to Degenerate Housewives. P(none) =0.0924

the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = 1-0.0924 = 0.9076

the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = 0.3359

If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)

No 33% is not unusual.