Asurveyor wants to find the distance from points a and b to an inaccessible point c. these three points form a triangle. because point c can be sighted from both a and b, he knows that the measure of < a= 53 degrees and the measure of < b = 61 degrees. in addition, the distance from a to b is 142 meters. find ac and bc. draw a diagram.

Part a)

Part b)

The diagram in the attached figure

Step-by-step explanation:

step 1

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

substitute the given values

step 2

Find the distance AC

Applying the law of sines

see the attached figure to better understand the problem

substitute the given values

---> rounded to the nearest hundredth

step 3

Find the distance BC

Applying the law of sines

substitute the given values

---> rounded to the nearest hundredth

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )