Justin and lincoln go to the movie theater and purchase refreshments for their friends. justin spends a total of $14.00 on 4 drinks and 4 bags of popcorn. lincoln spends a total of $20.50 on 8 drinks and 3 bags of popcorn. write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn. using these equations, determine and state the price of a bag of popcorn, to the nearest cent.

let's make p stand for popcorn and d for drinks. Using those variables, we can create our equations:

2p + 3d = 18.25

4p + 2d = 27.50

From this, we can use substitution or elimination to solve:

For substitution, in the second equations, we could factor out a 2, divide both sides by 2, and then move the left over 2p to the other side to isolate d to put into the first equation.

For elimination, we can multiply the first equation by -2 so that we can remove the 4p and focus on solving for d.

I'll be using elimination in this case:

-2(2p + 3d = 18.25) --> -4p - 6d = -36.50

-4p - 6d = -36.50

4p  + 2d = 27.50

-4d = -9.00

d = 2.25

4p + 2 * 2.25 = 27.50

4p + 4.50 = 27.50

4p = 23.00

p = 5.75

Now let's check our

2 * 5.75 + 3 * 2.25 = 18.25

11.50 + 6.75 = 18.25

18.25 = 18.25

So drinks cost $2.25 and popcorn $5.75

i would have to say it is c.

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.