Assume that it takes a college student an average of 10 minutes to find a parking spot in the main parking lot. assume also that this time is normally distributed with a standard deviation of 5 minutes. what time is exceeded by approximately 75% of the college students when trying to find a parking spot in the main parking lot?

75% of college students exceed 6.63 minutes when trying to find a parking spot.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 10 minutes

Standard Deviation, σ = 5 minutes

We are given that the distribution of time for parking is a bell shaped distribution that is a normal distribution.

Formula:

P(X < x) = 0.25

We have to find the value of x such that the probability is 0.25.

P(X < x)  

Calculation the value from standard normal z table, we have,  

Hence, 75% of college students exceed 6.63 minutes when trying to find a parking spot.

think the answer would beb

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: