Asimple random sample of 3,500 people age 18 or over is taken in a large town to estimate the percentage of people (age 18 and over in that town) who read newspapers. it turns out that 2,487 people in the sample are newspaper readers. the population percentage is estimated as

2,487/3,500 x 100% ≈ 71%

the standard error is estimated as 0.8 of 1%, because

3,500 x √0.71x0.29 ≈ 27, 27/3,500 x 100% ≈ 0.8 of 1 %

(a) is 0.8 of 1% the right se? answer yes or no, and explain.

(b) 71% ± 1.6% is a for the fill in the blanks and explain.