Mathematics, 24.12.2019 00:31 ghostlyfrost67p8u0ey

Acargo plane flew roundtrip from smithtown to johnsville. it took one hour less time to get there than it did to get back. the average speed on the trip was 280 mph. the average speed on the way back was 240 mph. how many hours did the trip take?

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Answer from: sunshinesmile71

13 hours

Step-by-step explanation:

Average speed = Distance traveled / time taken

⇒ Distance = Average speed × Time

d = s × t

For the first trip;

Average speed = 280 mph

d₁ = 280t₁ (1)

where;

d₁ is the distance covered to get to the destination

t₁ is the time taken to get to the destination

For the second trip;

Average speed = 240 mph

d₂= 240t₂ (2)

where;

d₂ is the distance covered on the way back

t₂ is the time taken on the way back

The trip is the same distance to and fro. Therefore,

d₁ = d₂

Substituting the equation for d₁ and d₂

280t₁ = 240t₂ (3)

It took one hour less time to get there than it did to get back, then,

t₁ = t₂ - 1

t₂ = t₁ + 1 (4)

Substituting equation (4) into equation (3)

280t₁ = 240(t₁ + 1)

280t₁ = 240t₁ + 240

280t₁ - 240t₁ = 240

40t₁ = 240

t₁ = 240/40

t₁ = 6 hours

From equation (4)

t₂ = t₁ + 1

t₂ = 6 + 1

t₂ = 7 hours

The total time for the trip is t₁ + t₂ = 6 + 7

= 13 hours

Answer from: Quest

rx and sx

step-by-step explanation:

All of the following are pairs of corresponding sides in similar triangles except

Answer from: Quest

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

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Acargo plane flew roundtrip from smithtown to johnsville. it took one hour less time to get there th...