Sum of the squares of two consecutive natural numbers is 313. find the numbers.

Set one: 12 and 13

Set two: -13 and - 12

Step-by-step explanation:

Let the smaller number = x

Let the larger number = x + 1

x^2 + (x + 1)^2 = 313             Remove the brackets on the left.

x^2 + (x^2 + 2x + 1) = 313      

x^2 + x^2 + 2x + 1 = 313      Collect like terms

2x^2 + 2x + 1 = 313              Subtract 313 from both sides

2x^2 + 2x + 1 - 313 = 313 - 313

2x^2 + 2x - 312 = 0              Divide by 2

x^2 + x - 156 = 0

factor

There are two sets of factors that work

Set One

x = 12

x + 1 = 13

Set Two

x = - 13

x+1 = -13 + 1 = - 12

The second set is where you will get your marks. Few people will remember to use the minus answer

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: