Astudent figures that he has a 69% chance of being let out of class late. if he leaves class late, there is a 84% chance that he will miss his train. what is the probability that he gets out of class late and misses the train?

P( MT and L) = P(Late) *P(MT) =0.69*0.84= 0.5796

So then we have a 57.96 % of chance of being late and miss the train.

Step-by-step explanation:

Data given

Let's define the following events:

L = Being late , MT = Miss the train

For this case we have the following probabilities given:

P(L)=0.69 , P(MT|L)=0.84

And for this case we can assume that is possibe miss the train just and only if we are late.

The multiplication rule (general multiplication rule) "is a way to find the probability of two events happening at the same time"

Let A and B two events. From the general multiplication rule we have this formula:

P( A and B) = P(B|A)P(A)=P(A|B)P(B)

Solution for the problem

For this case we want to find this probability P(MT and T)

And we can use the previous rule and we have this:

P( MT and L) = P(Late) *P(MT) =0.69*0.84= 0.5796

So then we have a 57.96 % of chance of being late and miss the train.

i believe the correct answer is b.