Find the approximate distance between line –2x + 2y = 8 and the point p (4, −2).

Hello,

-2x+2y=8==>y=x+4(1)
The perdicular passing trought (4,-2) is
y+2=-1(x-4)==>y=-x+2(2)
The intersection is
(1)-(2)==>2x+2=0==>x=-1 and y=-1+4=3
Q=(-1,3)
P=(4,-2)
Distance PQ= √(( -1-4)²+(3+2)²)=√50=7,0710678...

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