Q: john has four more nickles than dimes in his pocket, for a total of $1.25 . which equation could be used to determine the number of dimes , x , in his pocket ?
possible answers : a. 0.10(x + 4) + 0.05(x) = $ 1.25 , b. 0.05(x + 4) + 0.10(x) = $1.25
, c. 0.10(4x) + 0.05(x) = $1.25 , d. 0.05(4x) + 0.10(x) = $1.25

Step-by-step explanation:

so he has 4 more nickels then dimesand if dimes represent x, then his nickels wold be x + 4

nickels are worth 0.05 and dimes are worth 0.10and he has a total of 1.25...so ur equation would be : B. 0.05(x + 4) + 0.10(x)

entering that problem on the tube might get you an answer

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.