On a coordinate plane, a triangle has points j (negative 3, 9), l (negative 3, 2), and k (5, 2).

consider reflections of δjkl.

what line of reflection maps point k to point k' at (–5, 2)?

Y-axis.

Step-by-step explanation:

Given : On a coordinate plane, a triangle has points J (negative 3, 9), L (negative 3, 2), and K (5, 2).

After reflection the coordinates of point K'  = (-5 , 2)

Here the sign of x-coordinate changed from K to K' but the y-coordinated remained exactly same.

We know that when we reflect a figure across y-axis the sign of x-coordinate changes but y-coordinate remains same.

Rule for reflection across y-axis = (x,y) → (-x , y)

∴ The line of reflection maps point K to point K' at (–5, 2) = Y-axis.

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.