Listed below are prices in dollars for one night at different hotels in a certain region. find the range, variance, and standard deviation for the given sample data. include appropriate units in the results. how useful are the measures of variation for someone searching for a room? 226 126 258 174 91 89 196 86 the standard deviation of the sample data is

Step-by-step explanation:

Given is a list of prices in dollars for one night at different hotels in a certain region

To find range, variance and std deviation.

Mean155.75

Standard Error23.80782434

Median150

Mode#N/A

Standard Deviation67.33869616

Sample Variance4534.5

Kurtosis-1.593759971

Skewness0.344624422

Range172

Minimum86

Maximum258

Sum1246

Count8

Thus we find range = 172 $.  This gives an idea about the lowest and highest difference.

Variance = Average of squares of deviations from the mean=  4533.329 $^2gives us an idea about the dispersion of data.  This helps to have an idea about the price rise or low in different hotels

Std deviation is square root of variance 67.33 $ shows an idea about the dispersion and also coefficient of variation as a ratio of mean to std deviation.

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation:

answer: 819.89 miles across america

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