Which term of the sequence 2,4, is 256?

128

Step-by-step explanation:

Givens

a = 2

L = 256

d = 2

n = ?

Formula

L = a + (n - 1)*d

Solution

256 = 2 + (n - 1)*2       Subtract 2 from both sides

254 = (n - 1)*2              Divide by 2    

254/2 = n-1)*2/2           Do the division  

127 = n - 1                     Add 1 to both sides..  

128 = n

If this sequence is part of an arithmetic sequence, then its 128-th term would be 256.

Step-by-step explanation:

The two neighboring terms differ by a constant, 2. As a result, this sequence is likely an arithmetic sequence.

The formula for the general -th term of an arithmetic sequence with first term and common difference is:

.

In this case, that's equal to

.

Let that expression be equal to . Solve for :

(after dividing both sides by .)

Hence, if this sequence is part of an arithmetic sequence, then the 128-th term would be 256.

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