Ineed find the sum of the first 42 terms of the sequences (12, 16, 20,
a) 3,717
b) 3,948
c) 1,134
d) 4,032

B

Step-by-step explanation:

Note the common difference between consecutive terms of the sequence.

d = 16 - 12 = 20 - 16 = 4

This indicates the sequence is arithmetic with sum to n terms

= [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 12 and d = 4, thus

= [ (2 × 12) + (41 × 4) ]

                          = 21( 24 + 164) = 21 × 188 = 3948 → B

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

6 cars because if you have 8 and subtract 2 youll have 6 left over