Nan orchid show, seven orchids are to be placed along one side of the greenhouse. of the orchids, we see that the number of lineups of the orchids is example 1.2-13 there are four lavender orchids and three white orchids. considering only the color

35

Step-by-step explanation:

7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of  the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we  divide all options by the restrictions. The result is:

= 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.