Find the slope of the line that passes through points (2,7) and (2,-6)

Here, we are required to find the slope of the line that passes through points (2,7) and (2,-6).

The slope of a line is simply defined as the extent of change in its y- value with respect to a unit change in its x-value.

Mathematically, the slope, m is given as;

m = (y2 - y1)/(X2 - x1)

In this case, the slope, m is as follows;

m = (-6 - 7)/(2 - 2)

m = -13/0

Therefore, the slope is undefined and as such, there is no slope.

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m=undefined

Step-by-step explanation:

The formula to find the slope isn't very complicated. The formula is:

     y₂-y₁

m=

       x₂-x₁

You have the points (2,7) and (2,-6). In (2,7) 2 is your x and 7 is your y. Since (2,7) is your first coordinate set, we put 2 as our x₁ . We put 7 as our y₁ .

In (2,-6) 2 is your x and -6 is your y. Since (2,-6) is your second coordinate set, we put 2 as our x₂ . We put -6 as our y₂ .

Let's substitute all of these numbers in:

     -6-7       -13

m=  =

      2-2         0

So we have -13/0 .You would think that any number divided by                0 is 0, right?

                 No. Any number divided by 0 is undefined.

Therefore, you slope, m, would be:

m=undefined .

~Happy Holidays~ :)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

what is

step-by-step explanation: