On the basis of sample of 25 students in a large campus laboratory, it appears that 8 students smoke. a 95% ci estimate of the proportion of smokers in the lab is: a. [0.137, 0.503] b. [0.037, 0.050] c. [1.137, 1.503]

a. [0.137, 0.503]

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

A sample of 25 students in the lab, of whom 8 smoke. So

95% confidence interval

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The correct answer is:

a. [0.137, 0.503]

idk

step-by-step explanation:

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