Store 1 earned 10% of the money invested i it while store 2 lost 8% of the amount invested in it. the net total gain was $1,300. this year the respective quantities were +6%, +%5 and $2,250. find the merchants investment for each store

Store 1= $150

Store 2= $250

Step-by-step explanation:

Let the amount invested by store 1 be x while store 2 be y hence

10x-8y=1300 Eqn 1

Make x the subject of the formula for the first equation

10x=1300+8y divide both sides by 10

X=130+0.8y

6x+5y=2250 Eqn 2

Substituting where there’s x with 130+0.8y in equation 2 we obtain

6(130+0.8y)+5y=2250

780+4.8y+5y=2250

9.8y+780=2250

9.28y=2250-780=1470

Y=1470/9.8=150

X=130+0.8y= 130+0.8(150)=250

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

a is the right answer