Brainliestt asap! me : )

describe the end behavior and determine whether the graph represents an odd-degree or an even-degree polynomial function. then state the number of real zeros.

End Behavior:

As x goes to -∞, goes to -∞

As x goes to ∞, goes to ∞

The graph represents an odd-degree polynomial function

There are 4 real zeroes.

Step-by-step explanation:

For the end behavior, all we need do is look at the graph. As we go further left, the function will continue to approach -∞. As we go further right, the function will approach ∞.

An even function has the same end behavior on each side, while an odd function has different end behaviors on each side. As we found that the end behaviors were different, we can determine that the function is odd.

Looking at the graph, we can see that there are 4 zeroes. But how can a function with 4 zeroes be odd? In this case, this function would be an function. This specific one would have an as one of its factors.

1. y ⟶ -∞ as x ⟶ -∞ and y ⟶ ∞ as x ⟶ ∞

2. Odd degree

3. Five real zeros

Step-by-step explanation:

1. End behaviour

The end behaviour of a function is what happens to it as x ⟶ ∞ and as x ⟶ -∞.

Your graph points sharply down on the left-hand side and sharply up on the right-hand side.

In your graph, the end behaviour is

y ⟶ -∞ as x ⟶ -∞ and y ⟶ ∞ as x ⟶ ∞.

2. Even/odd degree polynomials

The degree of a polynomial is the term of highest order.

If the degree is even, the function is an even-degree polynomial.  

The end behaviour of an even-degree polynomial is such that the ends of the graph are either both up or both down.

For an odd-degree polynomial, one end of the graph is up and the other is down.

Your graph is one-side-up and one-side-down, so it represents an odd-degree polynomial.

3. Number of real zeros

A polynomial has as many zeros as its degree. Your polynomial is odd-degree, so it must have 1, 3, 5, 7, etc. zeros.

The graph crosses or touches the x-axis four times, so there are at least four real zeros. The fifth zero is either real or complex. It can't be complex, because complex zeros always occur in pairs.

The fifth zero must be a duplicate of one we already see, almost certainly the one at the origin.

So, your function has five real zeros.

As proof-of-concept, I devised a fifth-degree polynomial with the properties of your function. Its graph is similar to yours.

the system of inequity is

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

the solid line passing through the points (0,4) and (4,0).

the related equation of solid line is .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

the related equation of dashed line is

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be . the required inequality is

similarly, check the second related equation.

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is