The 7 a. m. flight from dallas to chicago is on time 75% of the time. fran created this spinner to simulate the scenario. fran spun the spinner three times to predict whether the flight will be on time or late next monday, tuesday, and wednesday. how should she interpret this outcome of the three spins: shaded-shaded-unshaded?

a. the flight will be late all three days.
b. the flight will be on time all three days.
c. the flight will be late on one of the three days.
d. the flight will be on time on one of the three days.

Choice C; The flight will be late on one of the three days.

Step-by-step explanation:

The flight is 75% of the time. This means that out of 4 flights, 3 are on time and  the result of Franc's spinner should reflect this fact, i.e his spinner should give 75% probability of flights on time.

Choice A says the flight is on time 0% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Choice B says the flight is on time 100% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Choice C says the flight is on time 66% of the time, which is close to 75%. Therefore this choice is close and correct.

Choice D says the flight is on time 30% of the time, This is not true, therefore this is not a correct interpretation of the three spins.

Thus only choice C is correct.

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

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