Consider this scenario: for each year t, the population of a forest of trees is represented by the function a(t) = 113(1.029)t. in a neighboring forest, the population of the same type of tree is represented by the function b(t) = 81(1.025)t.

which forest's population is growing at a faster rate?

The forest A is growing at a faster rate as it has a larger base (1.029).

Step-by-step explanation:

We have been given that for each year t, the population of a forest of trees is represented by the function . In a neighboring forest, the population of the same type of tree is represented by the function .

We know that an exponential growth function is in form , where,

y = Final value,

a = Initial value,

b = For growth base b is in form , where r represents rate in decimal form,

x = Time.

We know that the larger the base of an exponential function would be, the larger will be growth rate.

Upon looking at both functions, we can see that base of function is 1.029 and base of function is 1.025.

Since 1.029 is greater than 1.025, therefore, the forest population represented by function grows at a faster rate.

570, the answer is 570, hope it