The rectangle below has an area of 15k4+35k3+20k2 square meters
the width of the rectangle is equal to the greatest common monomial factor of 70y^870y 8 70, y, start superscript, 8, end superscript and 30y^630y 6 30, y, start superscript, 6, end superscript.

what is the length and width of the rectangle ?

Width: ,

Length:

Step-by-step explanation:

Consider the question: The rectangle below has an area of square meters

. The width of the rectangle (in meters) is equal to the greatest common monomial factor of and . What is the length and width of the rectangle ?

First of all, we will find the greatest common monomial factor of and to determine the width as:

The greatest common factor of number part is 15, 20 and 35 is 5. The greatest common factor of variable part is .

Since the greatest common monomial factor of and is , therefore, the width of the given rectangle is meters.

Since area of rectangle is product of length and width of rectangle, so we will divide area of given rectangle by width to find the length of rectangle:

Cancel out common factors:

Therefore, the length of the given rectangle is meters.

answer: 43/157

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step-by-step explanation: