The graph of a function is a parabola that has a minimum at the point (-3,9). which equation could represent the function?

a. g(x)=3(x-3)^2+9

b. g(x)=-1/2(x-3)^2+9

c. g(x)=-(x+3)^2+9

d. g(x)=2(x+3)^2+9

, which corresponds to answer D.

Step-by-step explanation:

Recall that the maximum or minimum of a parabola is always located at its vertex. Notice that all quadratic functions listed are given in what is called "vertex" form, since they explicitly show the vertex coordinates in their formulation:

where , and   stand for the x and y coordinates respectively of the vertex.

Examining all four options, we notice that in all four cases listed, the is correct (equal to positive 9), so we proceed to examine what the expression should look like for  :

Notice that when replace   with "-3", we end up with a sign change:

Therefore we find that the last two options can be candidates. Then we recall that the question also states that this should be a minimum. Then, for a parabola to have a minimum, its branches must go upwards, and this corresponds to a case in which the factor (leading coefficient) multiplying (x-x_v)^2 is positive. So in looking for such condition, we find that the very last option is the only one that verifies such.

Then, is the option we select.

the answer is 0.071

good luck! : d

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!