Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°c. a thermometer is randomly selected and tested. draw a sketch and find the temperature reading corresponding to upper p82, the 82nd percentile. this is the temperature reading separating the bottom 82% from the top 18 %.

0.915

Step-by-step explanation:

Given that the readings of  the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00 degrees°C.

Let X represent the reading of the thermometer

X is N(0.1)

Or X is a standard normal variate

we have to find 82nd percentile

i.e. we find z such that

Sketch is attached

82nd percentile is 0.915

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

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step-by-step explanation: