a point p(x, y) is such that its distance form the y-axis is equal to its distance
from the point a(3,2).show that y^2 - 4y - 6x + 13 = 0

Good evening,

Step-by-step

let D represent distance of P form the y-axis

D²=|x|² = x²

AP²=(x-3)²+(y-2)²

D² = AP² ⇌ x² = (x-3)²+(y-2)² ⇌ x² = (x²-6x+9)+(y²-4y+4)

⇌ 0 = -6x+9+y²-4y+4

⇌ y² - 4y - 6x + 13 = 0.

:)

false

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!