Asap:
write an equation of hyperbola with foci at (-1, 1) and (5, 1) and vertices at (0, 1) and (4, 1)

The answer to your question is

Step-by-step explanation:

Data

Foci   (-1, 1) and (5, 1) [A and B]

Vertices (0, 1) and (4, 1)  [C and D]

See the image below. From the image we can conclude that it is a horizontal hyperbola.

Equation

From the image calculate the center

The center is in the middle of the vertices   (2, 1)

Now, calculate a, a is the distance from the center to the vertices, a = 2

Calculate c, c is the distance from the center to the foci, c = 3

Calculate b with the pythagorean theorem    c² = a² + b²

                                                                          b² = c² - a²

                                                                          b² = 3² - 2²

                                                                          b² = 9 - 4

                                                                          b² = 5

Substitution

y + 11 = (1/4)(x + 16)

step-by-step explanation:

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )