The temperature of chicken soup is 192.7 degrees f. as it cools, the temperature of the soup decreases 2.3 degrees f per minute. what is the temperature of the soup after 25 minutes?

The answer to your question is Final temperature = 135.2 °F

Step-by-step explanation:

Data

Initial temperature = T₀ = 192.7°F

Rate of decreasement  =  2.3°F x t

Final temperature = T₂ = ?

Final time = t₂ = 25 min

Process

1.- Write an equation

    T₂ = T₀ - 2.3 t₂

2.- Substitute values given in the formula

     T₂ = 192.7 - (2.3 x 25)

3.- Simplify and result

      T₂ = 192.7 - 57.5

       T₂ = 135.2 °F

the temperature of the soup after 25 minutes is 137.5 degrees

Step-by-step explanation:

As it cools, the temperature of the soup decreases 2.3 degrees F per minute. This is a linear rate. The rate at which the temperature is decreasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 192.7 degrees

d = - 2.3 degrees (it is decreasing)

n = 25

We want to determine the value if the 25th term, T25. Therefore,

T25 = 192.7 -2.3 (25 - 1) = 192.7 - 2.3×24

T25 = 137.5 degrees

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3