What is the value of b that satisfies the equation below
3(b+4)-2(2b+3)=-4

C) 10

Step 1: Rewrite equation

3(b+4)-2(2B+3)=-4

Step 2: Distribute

3(b+4)-2(2B+3)=-4

3b+12-4b-6=-4

Step 3: Combine like terms

3b+12-4b-6=-4

-b+6=-4

Step 4: Get -b alone on the left side

To do this we need to subtract 6 on both sides

-b+6=-4
-6 -6

-b=-10

Step 5: Making b positive

Since b cannot be a negative value we need to multiply both -b and -10 by -1 to make it positive

-b=-10

-1(-b)=-1(-10)

b=10

This is the final answer!

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