What is the least common multiple of 27, 12, and 36

(LCM, Least Common Multiple) Means to find a multiple of 2 or more numbers and find the least amount that is the same multiple for all numbers.

To do this equation, we must list multiples of each number.

We should do at least 10 multiples to get accurate answers.

For Number 27, we have 27 as our first multiple, we must add 27 after our last sum.

27: 27, 54, 81, 108, 135, 162, 189, 216, 243, and 270.

Work/Proof:

0 +27 = 1st Multiple

27 + 27 = 2nd Multiple

54 + 27 = 3rd Multiple

81 + 27 = 4th Multiple

108 + 27 = 5th Multiple

135 + 27 = 6th Multiple

162 + 27 = 7th Multiple

189 + 27 = 8th Multiple

216 + 27 = 9th Multiple

243 + 27 = 10th Multiple

270.

(The sums are on the left before the plus. ( 54 + 27).

For Number 12, we have 12 as our first multiple, we must add 12 after our last sum.

12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120.

Work/Proof:

0 + 12 = 1st Multiple

12 + 12 = 2nd Multiple

24 + 12 = 3rd Multiple

36 + 12 = 4th Multiple

48 + 12 = 5th Multiple

60 + 12 = 6th Multiple

72 + 12 = 7th Multiple

84 + 12 = 8th Multiple

96 + 12 = 9th Multiple

108 + 12 = 10th Multiple

120.

For Number 36, we have 36 as our first multiple, we must add 36 after our last sum.

36: 36, 72, 108, 144, 180, 216, 252, 288, 324, 360.

Work/Proof:

0 + 36 = 1st Multiple

36 + 36 = 2nd Multiple

72 + 36 = 3rd Multiple

108 + 36 = 4th Multiple

144 + 36 = 5th Multiple

180 + 36 = 6th Multiple

216 + 36 = 7th Multiple

252 + 36 = 8th Multiple

288 + 36 = 9th Multiple

324 + 36 = 10th Multiple

360.

As we look at the multiples of each numbers, we see that 108 is a multiple that is the same with all numbers, it's the lowest common multiple:

27: 27, 54, 81, (108,) 135, 162, 189, 216, 243, and 270.

12: 12, 24, 36, 48, 60, 72, 84, 96, (108,) 120.

36: 36, 72, (108,) 144, 180, 216, 252, 288, 324, 360.

Best of Luck to you.

If you have any questions, feel free to comment below.

Happy New Year!

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option