Let y1 and y2 be independent and identically distributed with a uniform distribution over the interval (θ, θ + 1). for testing h0 : θ = 0 versus ha : θ > 0, we have two competing tests: test 1: reject h0 if y1 > .95. test 2: reject h0 if y1 + y2 > c. find the value of c so that test 2 has the same value for α as test 1. [hint: in example 6.3, we derived the density and distribution function of the sum of two independent random variables that are uniformly distributed on the interval (0, 1).]

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

the correct answers i think are b. and d.

give me brainliest if it is correct!

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

∡ eia and ∡ kij are congruent

step-by-step explanation: