If y ? -x, and every xi is i i d with a chi-squared distribution with 14 degrees of freedom, find the mgf of y m(t) = what is the distribution of y? select all that apply. there may be more than one correct answer a. chi squared(df 105) b. exponential(a 105 c. garnma(a = 2, ? = 210) d. gamma(a 1, 1/210) erponential(? = 210) f. chi-squared(df-210) g. gamma(a 105,b-2) h. garn ma(a-1, ? -1/105) i. none of the above

F. chi-squared(df-210)

Step-by-step explanation:

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

We have independent and identically distributed random chi square variables, each one with 14 degrees of freedom for . And let Y the random variable defined as :

We have a thorem that says that the distribution of Y is given by:

Proof

We need to find first the moment generating function for the random variable Y like this:

And the productory is satisfied because we have independent random variables. The moment generating function for a chi square distribution with r1 degrees of freedom is given by:

And replacing for each of the 15 distributions we got :

And using properties of algebra we got this:

And we can see that the moment generating function represent a chi square distribution with 14*15=210 degrees of freedom.  

So then the correct option is given by:

F. chi-squared(df-210)

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

the answers are in the images, i received 100% on this assignment. hope this !