The distance across a circular swimming pool is 56.68 ft. what is the distance from the edge of the pool to the center of the pool?

It sounds like we're given the diameter and asked for the radius, which is half.

28.34 ft

28.34 feet

Step-by-step explanation: In this problem, let's first start by drawing the circular swimming pool which I have attached in the image provided.

It's important to understand that the diameter is the distance across a circle so when the problem says that the distance across a circular swimming pool is 56.68 ft, we are dealing with the diameter.

Then, the problem is asking us to find the distance from the edge of the pool to the center of the pool. The distance from any point on a circle to the center is called the radius of the circle. So here, the distance from the edge of the pool to the center of the pool will be the radius.

The radius will always be 1/2 of the diameter so if we know the distance across which is 56.68, we simply divide by 2 and we get our answer.

All radii of a given circle are congruent so we can choose any point on the circle as long as it hits the center of the pool.

If we draw the radius, it will be exactly half of the diameter. The radius will be 28.34 feet which means the distance from the edge to the center is 28.34 ft.

ian gonna lie that is way to much

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752