An art project has an area of 63.6 square inches. what is the width, in inches, of the project?
a . 4.3
b . 4.8
c . 5.3
d . 5.8
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Option C . 5.3 in

Step-by-step explanation:

The complete question is

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles

Let

x ----> the length of the art project in inches

y ----> the width of the art project in inches

we know that

The area of the rectangular art project is equal to

we have

so

----> equation A

substitute the value of x in the equation A

solve for y

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: