Will mark brainliest and ! extra !

determine if lines jk and lm are parallel, perpendicular, or neither.

j(1,9), k(7,4), l(8,13), m(-2,1)

a. parallel

b. perpendicular

c. neither

determine if the lines are parallel, perpendicular, or neither.

4x +5y = 10 and 5x -4y =28

hint: solve for y

a. parallel

b. perpendicular

c. neither

1. Perpendicular; 2, perpendicular  

Step-by-step explanation:

1. Segments JK and LM

(a) Calculate the slopes of the segments

(i) Segment JK

(ii) Segment LM

(b) Compare their slopes

The two segments are perpendicular.

Their graphs are shown in Figure 1.

2. Equations

(a) Calculate the slopes of the segments

(i) First equation

4x + 5y = 10

5y = 10 - 4x

y = 2 - ⅘x

m₁ = -⅘

(ii) Second equation

5x - 4y = -28

-4y = -28 - 5x

y = 7 + ⁵/₄x

m₂ = ⁵/₄

(b) Compare the slopes

m₂ = ⁵/₄ = -1/m₁

The two lines are perpendicular.

The graphs are shown in Figure 2.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.