The perimeter of a rectangular lot is 74 feet. the cost of fencing along the two lengths is $1 per foot, and the cost of fencing along the two widths is $3.50 per foot. find the dimensions of the lot if the total cost of the fencing is $159.

340 ft²

Step-by-step explanation:

perimeter of rectangle = 2 x (L+W) = 2L + 2W = 74 (1)

cost of two length : $1 x 2L

cost of two width: $3.50 x 2W

($1 x 2L) + ($3.50 x 2W) = $159

2L + 7W = 159 (2)

(2) - (1) ...  5W = 85

W = 17

L = (74 - 2 x 17) / 2 = 20

dimension = 17 x 20 = 340 ft²

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.