Ann increased the quantities of all the ingredients in a recipe by 60\%60%60, percent. she used 808080 grams (\text{g})(g)left parenthesis, start text, g, end text, right parenthesis of cheese. how much cheese did the recipe require?

50 grams

Step-by-step explanation:

Let the amount of cheese required by the recipe be "x"

Ann increased 60% from original amount and then used up 80 grams. Thus:

Original, increased by 60%, became 80

This translated to algebraic equation would be:

x + 0.6x = 80

Note:  60% = 60/100 = 0.6

So we can solve the above equation for "x" and get our answer. Shown below:

Hence,

the recipe required 50 grams of cheese

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.