What is the equation of the line with m = 6 that goes through the point (1, 4)?
a. y – 4 = 6(x + 1)
b. y – 4 = 6(x – 1)
c. y + 4 = 6(x – 1)
d. y + 4 = 6(x + 1)

B) y-4=6(x-1)

Substitute the point into each equation

A: y-4=6(x+1)

4-4=6(1+1)

4-4=6+6

0=12

This is false so it is not the answer

B: y-4=6(x-1)

4-4=6(1-1)

4-4=6-6

0=0

This is true so this is the answer, but I will continue solving just to check

C: y+4=6(x-1)

4+4=6(1-1)

4+4=6-6

8=0

This is false so it is not the answer

D: y+4=6(x+1)

4+4=6(1+1)

4+4=6+6

8=12
This is not true so it is not the answer

Your answer becomes b, the only true equation! Hope this helps comment below for more questions :)

Where is the problems