The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. a sample of 30 bottles showed a standard deviation of .2. the p-value for the test is

a. 025
b. between .025 and .05
c. 05
d. between .05 and .01

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

the value that we want to test

represent the p value for the test

t represent the statistic

significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0:

H1:

In order to check the hypothesis we need to calculate the statistic given by the following formula:

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

What is the approximate p-value of the test?

The degrees of freedom are given by:

For this case since we have a right tailed test the p value is given by:

And the best option would be:

b. between .025 and .05

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16